25x^2-16x-63=0

Solution for 25x^2-16x-63=0 equation:

25x^2-16x-63=0

a = 25; b = -16; c = -63;
Δ = b2-4ac
Δ = -162-4·25·(-63)
Δ = 6556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6556}=\sqrt{4*1639}=\sqrt{4}*\sqrt{1639}=2\sqrt{1639}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{1639}}{2*25}=\frac{16-2\sqrt{1639}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{1639}}{2*25}=\frac{16+2\sqrt{1639}}{50}
$